Students can practice TS SCERT Class 6 Maths Solutions Chapter 10 Perimeter and Area InText Questions to get the best methods of solving problems.
TS 6th Class Maths Solutions Chapter 10 Perimeter and Area InText Questions
Try This
Question 1.
Give five examples of situations where you need to know the perimeter.
Answer:
- To construct the house.
- To pave the tiles of a room.
- To find the perimeter of a flat.
- To determine the perimeter of a field.
- To construct a well around the school ground. For the above cases the knowledge of concept of perimeter is required.
Do This
Question 1.
What would be the perimeter of these shapes ? Fill in the blanks given and in each case start from the point A.
Answer:
(i) Perimeter = AB + BC + CD + DA
= 10m + 40m + 10m + 40m
= 100 m
= 100m + 120m + 90m + 45m + 60m + 80m
= 495 m
Try This
Find the perimeter of the following :
Question 1.
A table with sides equal to 30 cm, 15 cm, 30 cm, 15 cm respectively.
Answer:
Perimeter of table = 2 (l + b)
= 2 (30cm + 15cm) = 2 (45)cm = 90 cms.
Question 2.
Measure the length of the sides of your text book cover. What is the perimeter ?
Answer:
The length of the sides of the text book (Maths) is 30 cm, 20 cm.
Its perimeter = 2 (l + b)
= 2 (30 + 20)cm
= 2 × 50cm
= 100 cms.
Question 3.
Around a rectangular park of sides 100 meters and 70 meters a wire has to be put. The cost of the wire is ₹ 20 per meter. What is the total cost of the wire ?
Answer:
Given that length of a park = 100 m
breadth of a park = 70 m
∴ Perimeter of a rectangular park = 2 (l + b)m
= 2 (100 + 70)m = 2 × 170m = 340 m.
The total cost of the wire at the rate of ₹ 20 perimeter = 340m × 20 = ₹ 6,800
Perimeter = AB + BC + £D + DA = 10m + 40m + 10m + 40m = 100 m
Try This
Question 1.
Find the perimeter of the following rectangles.
Answer:
Do This
Question 1.
A square picture frame has sides of 0. 75 mts. If the cost of a coloured paper is ₹ 20 per meter, what is the cost of putting coloured paper around the frame ?
Answer:
The side of sqaured frame = 0.75 m
Its perimeter =4 × s = 4 × 0.75 = 3m
∴ The cost of a coloured paper around the square frame at the rate of ₹ 20 per meter = 3 × 20 = ₹ 60.
Question 2.
There is a string of length 44 cm. How many different rectangles with positive integers as length and breadth can be made with this string ?
Answer:
The length and breadth of rectangle as follows whose perimeter is 44 cm.
| S.No. | Length | Breadth | Perimeter fin cm) |
| 1. | 10 | 12 | 44 |
| 2. | 9 | 13 | 44 |
| 3. | 8 | 14 | 44 |
| 4. | 7 | 15 | 44 |
| 5. | 12 | 10 | 44 |
Question 3.
If I have a string 41 cm long can I make a rectangle using the string completely ? Give reasons.
Answer:
| Length (cm) | Breadth (cm) | Perimeter (cm) |
| 10 | 10.5 | 41 |
| 9 | 11.5 | 41 |
| 11 | 9.5 | 41 |
| 13 | 7.5 | 41 |
| 14 | 6.5 | 41 |
Try These
Question 1.
Find the perimeter of the following squares. Figures are drawn on 1 cm grids.
Answer:
i) Perimeter of square ABCD = 4 × s = 4 × 4 = 16 cm.
ii) Perimeter of square PQRS = 4 × s = 4 × 6 = 24 cm.
iii) Perimeter of square EFGH = 4 × s = 4 × 5 = 20 cm.
iv) Perimeter of square WXYZ = 4 × s = 4 × 2 = 8 cm.
Question 2.
Find various objects from your surroundings which have regular shapes and their perimeters.
Answer:
The objects which are having the regular shapes are
1) A ‘4’ size squared paper.
2) The pentagon building in U.S.A.
3) A square shaped cake.
4) A square shaped field.
Do This
Question 1.
Find the perimeter of a regular pentagon of side 8 cm.
Answer:
Perimeter of a regular polygon = n × length of its side
∴ Perimeter of a pentagon = 5 × 8 cm = 40 cm
Try This
Question 1.
Find the areas of the following figures by counting squares.
Area of each square is 1 sq.cm
Answer:
| Figure | Its Area (in sq. cms) |
| (i) | 3 × 3 = 9 |
| (ii) | 7 × 1 = 7 |
| (iii) | 9 × 1 = 9 |
| (iv) | 8 × 1 = 8 |
| (v) | 6 × 1 = 6 |
| (vi) | 4 × 1 = 4 |
| (vii) | 4 × 1 = 4 |
| (viii) | 7 × 1 = 7 |
Do This
Question 1.
Trace shapes of leaves, flower petals and other such objects on the graph paper and find their area approximately.
Answer:
Student Activity
Question 2.
Draw any line diagram on a graph sheet. Count the squares and use them to estimate the area of the region.
Answer:
Student Activity
Try These
Question 1.
Draw two different rectangles having the same perimeter. Compare their areas. Are they same ? Can you draw two different squares having the same perimeter ?
Answer:
i) If the perimeters of two rectangles are equal then the areas of the rectangles need , not to be equal.
ii) No. We can’t draw two different squares having same perimeter. ;
Do This
Question 1.
Find the area of:
(i) The floor of your classroom.
(ii) A door in your house
(iii) The black board in your classroom.
Answer:
(i) Length of our class room floor = 15m
Breadth of the class room floor = 10m
Area of the floor = lb
= (15m) (10m)
= 150 sq.m
(ii) Length of the door in our house = 5m
Breadth of the door = 1.5 m
Area of the door = lb
= (5m) (1.5m)
= 7.5 sq.m
(iii) Length of the black board = 2.5m
Breadth of the black board = 2m
Area of the Black board = lb = 5sq.m
Try These
Question 1.
The length of one side of few squares are given. Find their areas using graph papers also find side × side. What do you notice from the result obtained ?
i) 4 cm
ii) 6 cm
iii) 2 cm
iv) 8 cm
Answer:
| Side of square (cms) | Its area by graph paper (sq. cm) | Side × Side |
| i) 4 cm | 4 + 4 + 4 + 4 = 16 | S × S = 4 × 4 = 16 |
| ii) 6 cm | 6 + 6 + 6 + 6 + 6 + 6 = 36 | S × S = 6 × 6 = 36 |
| iii) 2 cm | 1 + 1 + 1 + 1 = 4 | S × S = 2 × 2 = 4 |
| iv) 8 cm | 8 + 8 + 8 + 8 + 8 + 8 + 8 + 8 = 64 | S × S = 8 × 8 = 64 |
We notice that two results are equal.