TS 6th Class Maths Solutions Chapter 1 Knowing Our Numbers InText Questions

Students can practice TS 6th Class Maths Solutions Chapter 1 Knowing Our Numbers InText Questions to get the best methods of solving problems.

TS 6th Class Maths Solutions Chapter 1 Knowing Our Numbers Exercise InText Questions

Do This

Round off these numbers as directed:

Question 1.
48, 62, 81, 94, 27 to their nearest tens.
Answer:

  • 48 is nearer to 50 than 40. So it is rounded off to 50.
  • 62 is nearer to 60 than 70. So it is rounded off to 60.
  • 81 is nearer to 80 than 90. So it is rouhded off to 80.
  • 94 is nearer to 90 than 100. So it is rounded off to 90.
  • 27 is nearer to 30 than 20. So it is rounded off to 30.

TS 6th Class Maths Solutions Chapter 1 Knowing Our Numbers InText Questions

Question 2.
128, 275, 312, 695, 199 to their nearest hundreds.
Answer:
(i) 128 is nearer to 100 than 200.
So it is rounded off to 100.

(ii) 275 is nearer to 300 than 200.
So it is rounded off to 300.

(iii) 312 is nearer to 300 than 400.
So it is rounded off to 300.

(iv) 695 is nearer to 700 than 600.
So it is rounded off to 700.

(iv) 199 is nearer to 200 than 100.
So it is rounded off to 200.

Question 3.
7452, 8115, 3066, 7119, 9600 to their nearest thousands.
Answer:

  • 7452 is nearer to 7000 than 8000. So it is rounded off to 7000.
  • 8115 is nearer to 8000 than 9000. So it is rounded off to 8000.
  • 3066 is nearer to 3000 than 4000. So it is rounded off to 3000.
  • 7119 is nearer to 7000 than 8000. So it is rounded off to 7000.
  • 9600 is nearer to 10000 than 9000. So it is rounded off to 10000.

Think, Discuss and Write

Discuss with your friends about rounding off numbers for ten thousands place.
Answer:
Rani and Uma both of them visited the Panchayat Office on their way back home and they observed the particulars on the wall.
Population of the village = 9,989.
The value 9,989 rounding off ten thousand.
Similarly, 10,007, 10,009, 10,015, ………… etc., are round off ten thousand.

Page No. 10(4)

Expand a number using place value.
Recall how you expand a two digit, three digit, four digit and five digit number.

Question 1.
Expand 64
Answer:
TS 6th Class Maths Solutions Chapter 1 Knowing Our Numbers Intext Questions 1
= (6 × 10) + (4 × 1)
= 60 + 4

Question 2.
Expand 325
Answer:
TS 6th Class Maths Solutions Chapter 1 Knowing Our Numbers Intext Questions 2
= (3 × 100) + (2 × 10) + (5 × 1)
= 300 + 20 + 5

Question 3.
Expand 5078
Answer:
TS 6th Class Maths Solutions Chapter 1 Knowing Our Numbers Intext Questions 3
= (5 × 1000) + (0 × 100) + (7 × 10) + (8 × 1)
= 5000 + 0 + 70 + 8

TS 6th Class Maths Solutions Chapter 1 Knowing Our Numbers InText Questions

Question 4.
Expand 29500
Answer:
TS 6th Class Maths Solutions Chapter 1 Knowing Our Numbers Intext Questions 4
= (2 × 10000) + (9 × 1000) + (5 × 100) + (0 × 10) + (0 × 1)
= 20000 + 9000 + 500 + 0 + 0
= 20000 + 9000 + 500

D0 This

Now expand the numbers as given in the example.

Number Expansion Expanded form
21504 (2 × 10000) + (1 × 1000) + (5 × 100) + (0 × 10) + (4 × 1) 20000 + 1000 + 500 + 4
38400 (3 × 10000) + (8 × 1000) + (4 × 100) + (0 × 10) + (0 × 1) 30000 + 8000 + 400
77888 (7 × 10000) + (7 × 1000) + (8 × 100) + (8 × 10) + (8 × 1) 70000 + 7000 + 800 + 80 + 8
20050 (2 × 10000) + (0 × 1000) + (0 × 100) + (5 × 10) + (0 × 1) 20000 + 50
41501 (4 × 10000) + (1 × 1000) + (5 × 100) + (0 × 10) + (1 × 1) 40000 + 1000 + 500 + 1

Page No: 14 (6)
Write the following numbers in expanded form and the way of reading.
(i) 4,57,000
Answer:
Expanded form :
= (4 × 1,00,000) + (5 × 10,000) + (7 × 1000) + (0 × 100) + (0 × 10) + (0 × 1)
= 4,00,000 + 50,000 + 7,000

Read as:
Four lakh fifty seven thousand.

(ii) 3,05,400
Answer:
Expanded form :
(3 × 1,00,000) + (0 × 10,000) + (5 × 1000) + (4 × 100) + (0 × 10) + (0×1)
= 3,00,000 + 5,000 + 400

Read as:
Three lakh five thousand four hundred.

(iii) 3,09,390
Answer:
Expanded form :
= (3 × 1,00,000) + (0 × 10,000) + (9 × 1000) + (3 × 100) + (9 × 10) + (0 × 1)
= 3,00,000 + 0 + 9000 + 300 + 90 + 0

Read as:
Three lakh nine thousand three hundred ninety

(iv) 2,00,035
Answer:
Expanded form :
= (2 × 1,00,000) + (0 × 10,000) + (0 × 1000) + (0 × 100) + (3 × 10) + (5×1)
= 2,00,000 + 30 + 5

TS 6th Class Maths Solutions Chapter 1 Knowing Our Numbers InText Questions

Read as:
Two lakh thirty five.

(Try These)

Question 1.
Give any five examples using daily life situations where the number of things counted would be more than 6 digits.
Answer:

  • To calculate the population
  • To calculate the money which is more than 1 lakh
  • Count of white blood cells in the body
  • Count of cells in a leaf
  • Count of voters in Hyderabad city

Question 2.
Write the smallest and greatest of all two digit, three digit, four digit, five digit, six digit, seven digit, eight digit numbers.
Answer:

Digit Smallest number Greatest number
1. Two digit 10 99
2. Three digit 100 999
3. Four digit 1,000 9,999
4. Five digit 10,000 99,999
5. Six digit 1,00,000 9,99,999
6. Seven digit 10,00,000 99,99,999
7. Eight digit 1,00,00,000 9,99,99,999

Page No: 18

Question 1.
Read the numbers given below.
(i) 41430495
Answer:
4,14,30,495 = Four crore fourteen lakh thirty thousand four hundred ninety five.

(ii) 304512031
Answer:
30,45,12,031 = Thirty crore forty five lakh twelve thousand thirty one.

(iii) 241800240
Answer:
24,18,00,240 = Twenty four crore, eighteen lakh two hundred forty.

(iv) 69697100
Answer:
6,96,97,100 = Six crore ninety six lakh ninety seven thousand one hundred.

(v) 100091409
Answer:
10,00,91,409 = Ten crore, ninety one thousand four hundred nine.

Question 2.
Write the expansion of 12735045
Answer:
1,27,35,045 = (1×10000000) + (2 × 1000000) + (7 × 100000)+ (3 × 10000) + (5 × 1000) + (0 × 100) + (4 × 10) + (5 × 1)

TS 6th Class Maths Solutions Chapter 1 Knowing Our Numbers InText Questions

Do This:

Question 1.
Expand the numbers using commas,
(i) 999999999
Answer:
99,99,99,999
= (9 × 10,00,00,000) + (9 × 1,00,00,000) + (9 × 10,00,000) + (9 × 1,00,000) + (9 × 10,000) + (9 × 1,000) + (9 × 100) + (9 × 10) + (9×l)
= 90,00,00,000 + 9,00,00,000 + 90,00,000 + 9,00,000 + 90,000 + 9,000 + 900 + 90 + 9

(ii) 34530678
Answer:
3,45,30,678
= (3 × 1,00,00,000) + (4 × 10,00,000) + (5 × 1,00,000) + (3 × 10,000) + (0 × 1,000) + (6 × 100) + (7 × 10) + (8 × 1)
= 3,00,00,000 + 40,00,000 + 5,00,000 + 30,000 + 600 + 70 + 8

(iii) 510010051
Answer:
51,00,10,051
= (5 × 10,00,00,000) + (1 × 1 ,00,00,000) + (0 × 10,00,000) + (0 × 1,00,000) + (1 × 10,000) + (0 × 1000) + (0 × 100) + (5 × 10) + (1 × 1)
= 50,00,00,000 + 1,00,00,000 + 10,000 + 50 + 1

Question 2.
Read these numbers and write in words.
(i) 5,06,45,075
Answer:
Five crore six lakhs forty five thousand seventy five.

(ii) 12,36,99,140
Answer:
Twelve crore thirty six lakhs ninety nine thousand one hundred forty.

(iii) 2,50,00,350
Answer:
Two crore fifty lakhs three hundred fifty.

Try These

Question 1.
Name four important towns in your district. Note the distance between them in km. Express these in centimeters and millimeters.
Answer:

  • Armar
  • Bheemgal
  • Balkonda
  • Bodhan.

The distance between Armur and Bheemgal is 62 km.
1 km = 100000 cm
∴ 62 km = 62 × 100000 = 6200000 cm
= 6200000 × 10 = 62000000 mm (∵ 1cm = 10 mm)
The distance between Bheemgal and Balkonda is 29 km.
29 km = 29 × 100000 = 2900000 cm
= 2900000 × 10 mm = 29000000 mm
The distance between Balknoda and Bodhan is 66 km. .
66km = 66 × 100000= 6600000 cm
= 6600000 × 10 mm = 66000000 mm
The distance between Bodhan and Armur is 53 km.
53km = 53 × 100000 = 5300000 cm
= 5300000 × 10 mm = 53000000 mm

TS 6th Class Maths Solutions Chapter 1 Knowing Our Numbers InText Questions

Question 2.
Can you tell where we use milligrams?
Answer:
We use milligrams to measure

  • silver
  • gold
  • mercury
  • platinum, etc.

Question 3.
A box contains 1,00,000 tablets (medicine) each weighing 20 mg. What is the weight of all the tablets in the box in both grams and kilograms ?
Answer:
The weight of 1 tablet = 20 mg
The total weight of 1,00,000 tablets = 1,00,000 × 20 mg = 20,00,000 mg
= \(\frac{2000000}{1000}\) grams (∵1 gram = 1000 milli grams)
= 2000 grams
= \(\frac{2000}{1000}\) kgs (∵ 1 kg = 1000 grams)
= 2 kgs

Question 4.
A petrol tanker contains 20,000 litres of petrol. Express the quantity of petrol in kilolitres and millilitres.
Answer:
The quantity of petrol in a petrol tanker is 20,000 litres.
= \(\frac{20000}{1000}\) kiloliters (∵ 1000 litres = 1 kilolitre)
= 20 kilolitres
We know that 1 litre = 1000 millilitres
∴ 20000 litres = 20000 × 1000 millilitres
= 20000000 millilitres

Think, Discuss and Write

Question 1.
You live in Ahmedabad and you trav-elled 400 m by bus to reach the nearest station. Then you take a train to reach Gandhi Nagar which is 15 km. away. Then you take a cab to reach your aunt’s house which is 18 km. away.
(i) How much distance did you travel to reach your aunt’s house ?
(ii) If you travel for 7 days like this how much distance would you travel ?
Answer:
(i) Travelled by bus = 400 m
Travelled by train =15 km
Travelled by cab = 18 km
∴ I travelled to reach my aunt’s house = 400 m + 15 km + 18 km
= 33 km 400 m = 33.4 kms.

(ii) The distance travelled by me in 7 days = 7 × 33.4 kms
= 233.8 kms (or) 233 km 800 m

TS 6th Class Maths Solutions Chapter 1 Knowing Our Numbers InText Questions

Question 2.
Every child in your school bring a water bottle containing 2 litres of water. If all the water is poured into a container which has 2 kilo litre capacity of water it was found that it needed 600 litre more to be filled. How many children poured water bottles in the container ?
Answer:
Capacity of water container = 2 kilolitres
= 2 × 1000 lts = 2000 litres
Each student bring the capacity of water bottle = 2 lts.
Required water to fill the tank is = 600 l
Already filled water in the container
= (2000 – 600) litres = 1400 litres
∴ Number of children poured water in the container = \(\frac{1400}{2}\) = 700
∴ 700 children poured water bottles in the container.

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