Students can practice TS 6th Class Maths Solutions Chapter 2 Whole Numbers Ex 2.2 to get the best methods of solving problems.
TS 6th Class Maths Solutions Chapter 2 Whole Numbers Exercise 2.2
Question 1.
Give the results without actually performing the operations using the given information.
(i) 28 × 19 = 532 then 19 × 28 =
(ii) 1 × 47 = 47 then 47 × 1 =
(iii) a × b = c then b × a =
(iv) 58 + 42 = 100 then 42 + 58 =
(v) 85 + 0 = 85 then 0 + 85 =
(vi) a + b = d then b + a =
Answer:
(i) 28 × 19 = 532 then 19 × 28 = 532
(ii) 1 × 47 = 47 then 47 × 1 = 47;
(iii) a × b = c then b × a = c
(iv) 58 + 42 = 100 then 42 + 58 = 100
(v) 85 + 0 = 85 then 0 + 85 = 85
(vi) a + b = d then b + a = d
Question 2.
Find the sum by suitable rearrangement:
(i) 238 + 695 + 162
Answer:
238 + 695 + 162 = (238 + 162) + 695
= 400 + 695 = 1095
(ii) 154 + 197 + 46 + 203
Answer:
154 + 197 + 46 + 203
= (154 + 46) + (197 + 203) = 200 + 400 = 600
Question 3.
Find the product by suitable rearrangement.
(i) 25 × 1963 × 4
Answer:
25 × 1963 × 4 = (25 × 4) × 1963
= 100 × 1963
= 196300
(ii) 20 × 255 × 50 × 6
Answer:
20 × 255 × 50 × 6 = (20 × 50) × (255 × 6)
= 1000 × 1530
= 1530000
Question 4.
Find the value of the following:
(i) 368 × 12 + 18 × 368
Answer:
(368 × 12) + (18 × 368)
= 368 × [12 + 18]
= 368 × 30
= 11040
(ii) 79 × 4319 + 4319 × 11
Answer:
(79 × 4319) + (4319 × 11)
= 4319 × [79 + 11]
= 4319 × 90
= 388710
Question 5.
Find the product using suitable properties:
(i) 205 × 1989
Answer:
1989 × 205 = 1989 × (200 + 5) = (1989 × 200) + (1989 × 5)
= 397800 + 9945 = 407745
(ii) 1991 × 1005
Answer:
1991 × 1005 = 1991 × [1000 + 5] = (1991 × 1000) + (1991 × 5)
= 1991000 + 9955 = 2000955
Question 6.
A milk vendor supplies 56 liters of milk in the morning and 44 liters of milk in the evening to a hostel. If the milk costs ₹ 30 per liter, how much money he gets per day?
Answer:
Quantity of milk supplied to the hostel in the morning = 56 litres
Quantity of milk supplied to the hostel in the evening = 44 litres
Quantity of milk supplied to the hostel per day = (56 + 44) litres = 100 litres
Cost of 1 litre of milk = ₹ 30
Cost of 100 litres of milk = ₹ 30 × 100 = ₹ 3000
Question 7.
Chandana and Venu purchased 12 note books and10 note books respectively. The cost of each note book is ₹ 15,then how much amount should they pay to the shop keeper?
Answer:
Cost of one note book = ₹ 15
Number of note books that Chandana bought =12
Amount that Chandana has to pay the shopkeeper = ₹ 15 × 12
Number of notebooks that Venu bought = 10
Amount that Venu has to pay to the shopkeeper = ₹ 15 × 10
Total amount that Chandana and Venu have to pay the shopkeeper =
₹ 15 × 12 + ₹ 15 × 10 = ₹ 15 [12 + 10] = ₹ 15 × 22 = ₹ 330
Question 8.
Match the following:
(i) 1991 + 7 = 7 + 1991 | (a) Additive identity |
(ii) 68 × 50 = 50 × 68 | (b) Multiplicative identity |
(iii) 1 | (c) Commutative under addition |
(iv) 0 | (d) Distributive property of multiplication over addition |
(v) 879 × (100 + 30) = 879 × 100 + 879 × 30 | (e) Commutative under multiplication |
Answer:
(i) 1991 + 7 = 7 + 1991 | (c) Commutative under addition |
(ii) 68 × 50 = 50 × 68 | (e) Commutative under multiplication |
(iii) 1 | (b) Multiplicative identity |
(iv) 0 | (a) Additive identity |
(v) 879 × (100 + 30) = 879 × 100 + 879 × 30 | (d) Distributive property of multiplication over addition |