Students can practice Telangana SCERT Class 6 Maths Solutions Chapter 13 Practical Geometry Ex 13.4 to get the best methods of solving problems.

## TS 6th Class Maths Solutions Chapter 13 Practical Geometry Exercise 13.4

Question 1.

Draw the following angles with the help of a protractor.

(i) ∠ABC = 65°

Answer:

∠ABC = 65°

Steps of construction:

- Draw a ray BC of any length.
- Place the centre point of the protractor at B and the line aligned with the \(\overrightarrow{\mathrm{BC}}\).
- Mark a point A at 65°.
- Join BA. ∠ABC is the required angle.

(ii) ∠PQR = 136°

Answer:

∠ PQR = 136°

Steps of construction:

- Draw a ray QR of any length.
- Place the centre point of the protractor at Q and the line aligned with the \(\overrightarrow{\mathrm{QR}}\).
- Mark a point P at 136°.
- Join QP. ∠PQR is the required angle.

(iii) ∠Y = 45°

Answer:

∠Y = 45°

Steps of construction:

- Draw a ray YZ of any length.
- Place the centre point of the protractor

at Y and the line aligned with the \(\overrightarrow{\mathrm{YZ}}\). - Mark a point X at 45°.
- Join YX. ∠XYZ is the required angle.

(iv) ∠O =172°

Answer:

∠O = 172°

Steps of construction:

- Draw a ray OP of any length.
- Place the centre point of the protractor at 0 and the line aligned with the OP
- Mark a point N at 172°.
- Join ON. ∠NOP is the required angle.

Question 2.

Copy the following angles in your notebook and find their bisector.

Answer:

Steps of construction :

- Draw a line l and choose a point P on it.
- Now place the compasses at A and draw an arc to cut the rays AC and AB.
- Use the same compasses setting to draw an arc with P as centre, cutting / at Q.
- Set your compasses with \(\overline{\mathrm{BC}}\) as the radius.
- Place the compasses pointer at Q and draw an arc to cut the existing arc at R.
- Join PR. This gives us ∠RPQ. It has the same measure as ∠CAB.

This means ∠QPR has same measure as ∠BAC. - Take Q as centre and with radius more than half of the length PQ, draw an arc. Now take R as centre and with the same radius, draw another arc intersecting the previous arc at S. Join PS. PS is the bisector of the given angle.