TS 6th Class Maths Solutions Chapter 13 Practical Geometry Ex 13.4

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Students can practice Telangana SCERT Class 6 Maths Solutions Chapter 13 Practical Geometry Ex 13.4 to get the best methods of solving problems.

TS 6th Class Maths Solutions Chapter 13 Practical Geometry Exercise 13.4

Question 1.
Draw the following angles with the help of a protractor.
(i) ∠ABC = 65°
Answer:
∠ABC = 65°
TS 6th Class Maths Solutions Chapter 13 Practical Geometry Ex 13.4 1

Steps of construction:

  1. Draw a ray BC of any length.
  2. Place the centre point of the protractor at B and the line aligned with the \(\overrightarrow{\mathrm{BC}}\).
  3. Mark a point A at 65°.
  4. Join BA. ∠ABC is the required angle.

TS 6th Class Maths Solutions Chapter 13 Practical Geometry Ex 13.4

(ii) ∠PQR = 136°
Answer:
∠ PQR = 136°
TS 6th Class Maths Solutions Chapter 13 Practical Geometry Ex 13.4 2

Steps of construction:

  1. Draw a ray QR of any length.
  2. Place the centre point of the protractor at Q and the line aligned with the \(\overrightarrow{\mathrm{QR}}\).
  3. Mark a point P at 136°.
  4. Join QP. ∠PQR is the required angle.

(iii) ∠Y = 45°
Answer:
∠Y = 45°
TS 6th Class Maths Solutions Chapter 13 Practical Geometry Ex 13.4 3

Steps of construction:

  1. Draw a ray YZ of any length.
  2. Place the centre point of the protractor
    at Y and the line aligned with the \(\overrightarrow{\mathrm{YZ}}\).
  3. Mark a point X at 45°.
  4. Join YX. ∠XYZ is the required angle.

TS 6th Class Maths Solutions Chapter 13 Practical Geometry Ex 13.4

(iv) ∠O =172°
Answer:
∠O = 172°
TS 6th Class Maths Solutions Chapter 13 Practical Geometry Ex 13.4

Steps of construction:

  1. Draw a ray OP of any length.
  2. Place the centre point of the protractor at 0 and the line aligned with the OP
  3. Mark a point N at 172°.
  4. Join ON. ∠NOP is the required angle.

Question 2.
Copy the following angles in your notebook and find their bisector.
TS 6th Class Maths Solutions Chapter 13 Practical Geometry Ex 13.4 5
Answer:
TS 6th Class Maths Solutions Chapter 13 Practical Geometry Ex 13.4 6
Steps of construction :

  1. Draw a line l and choose a point P on it.
  2. Now place the compasses at A and draw an arc to cut the rays AC and AB.
  3. Use the same compasses setting to draw an arc with P as centre, cutting / at Q.
  4. Set your compasses with \(\overline{\mathrm{BC}}\) as the radius.
  5. Place the compasses pointer at Q and draw an arc to cut the existing arc at R.
  6. Join PR. This gives us ∠RPQ. It has the same measure as ∠CAB.
    This means ∠QPR has same measure as ∠BAC.
  7. Take Q as centre and with radius more than half of the length PQ, draw an arc. Now take R as centre and with the same radius, draw another arc intersecting the previous arc at S. Join PS. PS is the bisector of the given angle.

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