TS 10th Class Maths Solutions Chapter 14 Statistics Ex 14.4

Students can practice 10th Class Maths Textbook SSC Solutions Telangana Chapter 14 Statistics Ex 14.4 to get the best methods of solving problems.

TS 10th Class Maths Solutions Chapter 14 Statistics Exercise 14.4

Question 1.
The following distribution gives the daily income of 50 workers of a factory.

Daily income (in Rupees)250-300300-350350-400400-450450-500
Number of workers12148610

Convert the distribution above to a less than type cumulative frequency distribution and draw its ogive. (AS5)
Solution:
For less than ogive, we take the upper class limits on X-axis and their corresponding cumulative frequencies on Y – axis, choosing a convenient scale.

Daily income (in Rupees)250-300300-350350-400400-450450-500
Number of workers12148610
Class Interval (Upper Limits)frequencycumulative frequencyPoints
3001212(300, 12)
3501426(350, 26)
400834(400, 34)
450640(450, 40)
5001050(500, 50)

The points to be plotted are (300, 12) (350, 26) (400, 34) (450, 40) and (500, 50)
Scale :
On X-axis : 1 cm = 50 units
On Y-axis : 1 cm = 5 units
TS 10th Class Maths Solutions Chapter 14 Statistics Ex 14.4 1

Question 2.
During the medical check-up of 35 students of a class, their weights were recorded as follows : (AS5)

Weight (in kg)Number of students
Less than 380
Less than 403
Less than 425
Less than 449
Less than 4614
Less than 4828
Less than 5032
Less than 5235

Draw a less than type ogive for the given data. Hence obtain the median weight from the graph and verify the result by using the formula.
Solution:
The points to be plotted on a graph paper are : (38, 0), (40, 3), (42, 5), (44, 9), (46, 14), (48, 28), (50, 32), (52, 35)
Scale :
On X-axis : 1 cm = 2 units
On Y-axis : 1 cm = 2 units
TS 10th Class Maths Solutions Chapter 14 Statistics Ex 14.4 2
Number of observations = 35
Here \(\frac{\mathrm{n}}{2}\) = \(\frac{35}{2}\) = 17.5
Locate the point 17.5 on the Y – axis. From the point, draw a line parallel to the X – axis cutting the curve at a point. From the point, draw a perpendicular to the X – axis.

TS 10th Class Maths Solutions Chapter 14 Statistics Ex 14.4

The point of intersection of this perpendicular with the X – axis determines the median of the given data as 46.8 kg.

WeightNumber of Students (c.f)Frequency (f)
Below 3800
38-4033
40-4252
42-4494
44-46145
46-482814
18-50324
50-52353

Number of observations = n = 35
\(\frac{\mathrm{n}}{2}\) = \(\frac{35}{2}\) = 17.5
17.5 belongs to the class 46 – 48
∴ Median class = 46 – 48
l – lower boundary of class = 46
f – frequency of the median class = 14
c.f. = 14
Class size = 2
Median = l + \(\frac{\left(\frac{n}{2}-c . f .\right)}{f}\) × h
= 46 + \(\frac{17.5-14}{14}\) × 2
= 46 + \(\frac{3.5}{14}\) × 2
= 46 + \(\frac{7}{14}\) = 46 + \(\frac{1}{2}\) = 46.5
Hence, median is 46.5 either ways.

TS 10th Class Maths Solutions Chapter 14 Statistics Ex 14.4

Question 3.
The following table gives production yield per hectare of wheat of 100 farms of a village. (AS5)

Production yield (Qui/Hec)50-5555-6060-6565-7070-7575-80
Number of farmers2812243816

Change the distribution to a more than type distribution and draw its ogive.
Solution:
More than type distribution
TS 10th Class Maths Solutions Chapter 14 Statistics Ex 14.4 3
Points to be plotted on the graph paper are:
(50, 100), (55, 98), (60, 90), (65. 78), (70, 54) and (75, 16)
Scale:
On X-axis: 1 cm = 5 units
On Y-axis: 1 cm = 10 units
TS 10th Class Maths Solutions Chapter 14 Statistics Ex 14.4 4

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