TS 6th Class Maths Solutions Chapter 11 Ratio and Proportion Ex 11.2

Students can practice TS SCERT Class 6 Maths Solutions Chapter 11 Ratio and Proportion Ex 11.2 to get the best methods of solving problems.

TS 6th Class Maths Solutions Chapter 11 Ratio and Proportion Exercise 11.2

Question 1.
Among the following, which ratios are in the simplest form ? If not, convert them into the simplest form.
(i) 2 : 3
(ii) 16 : 20
(iii) 5 : 6
(iv) 20 : 60
(v) 8 : 15
(vi) 19 : 2
Answer:
Simplest form:
(i) 2 : 3,
(iii) 5 : 6,
(v) 8 : 15,
(vi) 19 : 2

Convert form:
(ii) \(\frac{16}{4}: \frac{20}{4}\) (i.e) 4 : 5
(iv) \(\frac{20}{20}: \frac{60}{20}\) (i.e) 1 : 3

TS 6th Class Maths Solutions Chapter 11 Ratio and Proportion Ex 11.2

Question 2.
A bag contains 20 kg of rice and another bag contains 60 kg of wheat. Find the ratio of the amount of rice to that of wheat. What is the ratio of rice to the total weight ?
Sol.
Quantity of rice = 20 kg
Quantity of wheat = 60 kg
Ratio of the amount of rice to that of wheat
= 20 : 60
= 1 : 3
Total weight of bag containing rice and wheat = 20 + 60 = 80 kg
Ratio of rice to the total weight
= 20 : 80
= 1 : 4

Question 3.
There are 32 students in a class out of which 12 are girls. Find :
(i) The ratio of number of boys to number of girls.
Answer:
Total number of students in the class = 32
Number of girls in the class = 12
Number of boys in the class
= 32 – 12 = 20
The ratio of number of boys to number of girls = 20 : 12
= \(\frac{20}{4}: \frac{12}{4}\) = 5 : 3

(ii) The ratio of number of boys to total number of students.
Answer:
The ratio of number of boys to total number of students = 20 : 32
= \(\frac{20}{4}: \frac{32}{4}\) = 5 : 8

(iii) The ratio of number of girls to total number of students.
Answer:
The ratio of number of girls to total number of students = 12:32
= \(\frac{12}{4}: \frac{32}{4}\) = 3 : 8

Question 4.
Draw a four sided closed figure and divide it into some number of equal parts. Shade the figure with any colour so that the ratio of shaded parts to unshaded parts 1 : 3. Draw two more different figures and do the same.
Answer:
TS 6th Class Maths Solutions Chapter 11 Ratio and proportion Ex 11.2 1
Number of shaded parts = 3
Number of unshaded parts = 9
Ratio of shaded parts to unshaded parts = 3 : 9 = \(\frac{3}{3}: \frac{9}{3}\) = 1:3
Number of shaded parts = 2
Number of unshaded parts = 6
TS 6th Class Maths Solutions Chapter 11 Ratio and proportion Ex 11.2 2
Ratio of shaded parts to unshaded parts = 2 : 6 = \(\frac{2}{2}: \frac{6}{2}\) = 1 : 3
Number of shaded parts = 4
Number of unshaded parts = 12
Ratio of shaded parts to un shaded parts = 4 : 12
= \(\frac{4}{4}: \frac{12}{4}\) = 1 : 3
TS 6th Class Maths Solutions Chapter 11 Ratio and proportion Ex 11.2 3

TS 6th Class Maths Solutions Chapter 11 Ratio and Proportion Ex 11.2

Question 5.
Imran bought 2 litres of oil and Vijay bought 500 ml of oil. Find the ratio of quantities of oil bought by Imran to oil bought by Vijay.
Answer:
Quantity of oil bought by Imran
= 2 litres = 2 × 1000 ml = 2000 ml
Quantity of oil bought by Vijay = 500 ml
The ratio of quantities of oil bought by Imran to oil bought by Vijay
= 2000 : 500
= \(\frac{2000}{500}: \frac{500}{500}\) = 4 : 1

Question 6.
Weight of Abraham is 20 kg and his father’s weight is 60 kg. Find the ratio of weight of Abraham and his father. Express it in the simplest form.
Answer:
Weight of Abraham = 20 kg
Weight of Abraham’s father = 60 kg
Ratio of weight of Abraham and his father = 20 : 60
= \(\frac{20}{20}: \frac{60}{20}\) = 1 : 3
∴ The simplest form is 1:3.

Question 7.
Ramu spent \(\frac{2}{5}\) th of his money on a story book. Find the ratio of money spent to the money with him at the beginning.
Answer:
Let the money with Ramu be Rs. 1.
Then money spent by Ramu on a story book = Rs. 1 × \(\frac{2}{5}\) = Rs. \(\frac{2}{5}\)
The ratio of money spent to the money with him at the beginning = \(\frac{2}{5}\) : 1
= \(\frac{2}{5}\) × 5 : 1 × 5 = 2 : 5

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