Students can practice TS Class 10 Maths Solutions Chapter 7 Coordinate Geometry Ex 7.4 to get the best methods of solving problems.
TS 10th Class Maths Solutions Chapter 7 Coordinate Geometry Exercise 7.4
Question 1.
Find the slope of the line passing the two given points.
i) (4, -8) and (5, – 2)
Solution:
Slope = \(\frac{\mathrm{y}_2-\mathrm{y}_1}{\mathrm{x}_2-\mathrm{x}_1}\) = \(\frac{-2+8}{5-4}\) = \(\frac{6}{1}\) = 6
ii) (0, 0) and (\(\sqrt{3}\), 3)
Solution:
Slope = \(\frac{y_2-y_1}{x_2-x_1}\) = \(\frac{3-0}{\sqrt{3}-0}\)
iii) (0, 0) and (\(\sqrt{3}\), 3)
Solution:
Slope = \(\frac{y_2-y_1}{x_2-x_1}\) = \(\frac{-b-3 b}{a-2 a}\)
iv) (a, 0) and (0, b)
Solution:
Slope = \(\frac{\mathrm{y}_2-\mathrm{y}_1}{\mathrm{x}_2-\mathrm{x}_1}\) = \(\frac{b-0}{0-a}\) = \(\frac{-b}{a}\)
v) A(-1.4, -3.7) and B(-2.4, 1.3)
Solution:
Slope = \(\frac{\mathrm{y}_2-\mathrm{y}_1}{\mathrm{x}_2-\mathrm{x}_1}\) = \(\frac{1.3+3.7}{-2.4+1.4}\)
= \(\frac{5.0}{-1}\) = -5
vi) A(3,-2) and B(-6,-2)
Solution:
Slope = \(\frac{y_2-y_1}{x_2-x_1}\) = \(\frac{-2+2}{-6-3}\) = 0
vii)
Solution:
viii) A(0, 4), B(4, 0)
Solution:
Slope = \(\frac{\mathrm{y}_2-\mathrm{y}_1}{\mathrm{x}_2-\mathrm{x}_1}\)
= \(\frac{0-4}{4-0}\)
