Students can practice TS 6th Class Maths Solutions Chapter 4 Basic Geometrical Ideas InText Questions to get the best methods of solving problems.
TS 6th Class Maths Solutions Chapter 4 Basic Geometrical Ideas InText Questions
Do This
Question 1.
Four points are marked in the given rectangle. Name them.
Answer:
Their names taken as P, Q, R, S.
Question 2.
Take a geo-board. Select any two nails and tie tightly a thread from one end to the other. The thread you have fixed is a line which can extend in both directions and only in these two directions.
Answer:
Student activity
Think: Discuss And Write
Question 1.
Here is a ray \(\overrightarrow{\mathrm{O A}}\). It starts at O and passes through the points A and B.
Can you name ray \(\overrightarrow{\mathrm{O A}}\) as \(\overrightarrow{\mathrm{O B}}\)? Why?
Can you write the ray \(\overrightarrow{\mathrm{O A}}\) as \(\overrightarrow{\mathrm{A O}}\) ? Why ? Give reasons.
Answer:
The above ray starts from the point ‘O’ towards B so, it is named as \(\overrightarrow{\mathrm{O B}}\).
\(\overrightarrow{\mathrm{OA}} \neq \overrightarrow{\mathrm{AO}}\) since the ray starts from 0 i.e., it should be represented by only \(\overrightarrow{\mathrm{O A}}\).
Think. Discuss And Write
Question 1.
Move your pencil along the following English letters and state which are open and which are closed?
Answer:
D and O are closed letters
G, L, M are open letters.
Question 2.
Tell which letter is an example of simple curve.
Answer:
O is an example of simple curve.
Try These
Question 1.
Identify which are simple curves and which are not?
Answer:
(i) and(ii) are simple curves.
(iii) and (iv) are not simple curves.
Do This
Question 1.
Take some match sticks and try to make simple figures. Identify closed figures in them.
Answer:
Question 2.
What is the least number of sticks needed to form a closed figure ? Obviously three. Can you explain why two match sticks can not make a closed figure.
Answer:
Minimum number of sticks that are needed to form a closed figure are 3. If we take less than 3 sticks it will become a open figure.
Question 3.
Take some straw pieces of diffrent size. Pass thread into any 3 pieces and make different triangles. Draw figures for the tiangles in your notebook.
Answer:
Think, Discuss And Write
Question 1.
Take four points A, B, C and D such that A, B, C lie on the same line and D is not on it. Can the four line segments \(\overline{\mathrm{A B}}, \overline{\mathrm{B C}}, \overline{\mathrm{C D}}\) and \(\overline{\mathrm{AD}}\) form a quadrilateral? Give reason.
Answer:
No, the given four line segments \(\overline{\mathrm{A B}}, \overline{\mathrm{B C}}, \overline{\mathrm{C D}}\) and \(\overline{\mathrm{AD}}\)
Can not form a quadrilateral.
To form a quadrilateral maximum two points should be collinear.
Do This
Question 1.
Draw a circle on a paper and cut ¡t along its edge. Fold it Into half and again fold it to one fourth to make folding marks as shown.
You will observe a point in the middle. Mark this O. This is the centre of the circle. You can also indicate its radius. How many radii can you draw in a circle ?
Answer:
Infinite number of radii we can draw in a circle.
Because infinite number of points are there on the circumference of the circle.
Question 2.
Draw a circle and draw at least 5 chords in it. Make sure at least one of them passes through the centre. Name them and fill the table.
| S.No. | Chord | Length | Passes through the centre (Yes/No) |
| 1 | |||
| 2 | |||
| 3 | |||
| 4 | |||
| 5 |
What do you notice?
Answer:
| S.No | Chord | Length | Passes through the centre (Yes/No) |
| 1 | AB | 5 | Yes |
| 2 | CD | 2 | No |
| 3 | EB | 1.5 | No |
| 4 | GH | 2.7 | No |
| 5 | FT | 2 | No |
I notice that a chord which passes through the centre of the circle is the largest chord of all the chords.
Think And Discuss
Question 1.
Is it possible to draw more than one diameter in a circle ? Are all the diameters equal in length ? Discuss with your friends and find the answer.
Answer:
We can draw infinite number of diameters in a circle.
All the lengths of diameters are equal in a circle.
Since \(\overline{\mathrm{AF}}=\overline{\mathrm{BG}}=\overline{\mathrm{CH}}\) = 2.5 cm