Students can practice Telangana SCERT Class 6 Maths Solutions Chapter 13 Practical Geometry Ex 13.3 to get the best methods of solving problems.

## TS 6th Class Maths Solutions Chapter 13 Practical Geometry Exercise 13.3

Question 1.

Draw a line segment PQ = 5.8 cm and construct its perpendicular bisector using ruler and compasses.

Answer:

Steps of construction:

- Draw a line segment \(\overline{\mathrm{PQ}}\) = 5.8 cm.
- Take P as centre and radius more than half of PQ draw two arcs above and below the line segment \(\overline{\mathrm{PQ}}\).
- Take Q as centre and with the same radius, draw two more arcs intersecting the previous arcs at A and B.
- Join A and B. This line intersects PQ at O.
- AB is the required perpendicular bisector of the line PQ.

Question 2.

Ravi made a line segment of length 8.6 Find the length of AC and BC.

Answer:

Steps of construction :

- Draw a line segment AB = 8.6 cm.
- Take A as centre and radius more

than half of the length AB, draw two arcs above and below the line segment AB. , - Take B as cfentre and with the same radius, draw two more arcs intersecting the previous- arcs at P and Q.
- Join PQ. This line intersects AB at C.
- Measure AC and BC. On measuring, it is noticed that AC = BC = 4.3 cm.

Question 3.

Using ruler and compasses, draw AB = 6.4 cm. Find its mid point.

Answer:

We can find the mid point of the line segment AB = 6.4 cm by drawing its perpendicular bisector.

Steps of construction:

- Draw a line segment AB = 6.4 cm.
- Take A as centre and radius more than half of the length AB draw two arcs above and below the line segment AB.
- Take B as centre and with the same radius draw two more arcs intersecting the previous arcs at M and N.
- Join MN. This line intersects AB at O. ‘O’ is the mid point of AB.