TS 6th Class Maths Solutions Chapter 13 Practical Geometry Ex 13.3

Students can practice Telangana SCERT Class 6 Maths Solutions Chapter 13 Practical Geometry Ex 13.3 to get the best methods of solving problems.

TS 6th Class Maths Solutions Chapter 13 Practical Geometry Exercise 13.3

Question 1.
Draw a line segment PQ = 5.8 cm and construct its perpendicular bisector using ruler and compasses.
Answer:
TS 6th Class Maths Solutions Chapter 13 Practical Geometry Ex 13.3 1

Steps of construction:

  1. Draw a line segment \(\overline{\mathrm{PQ}}\) = 5.8 cm.
  2. Take P as centre and radius more than half of PQ draw two arcs above and below the line segment \(\overline{\mathrm{PQ}}\).
  3. Take Q as centre and with the same radius, draw two more arcs intersecting the previous arcs at A and B.
  4. Join A and B. This line intersects PQ at O.
  5. AB is the required perpendicular bisector of the line PQ.

TS 6th Class Maths Solutions Chapter 13 Practical Geometry Ex 13.3

Question 2.
Ravi made a line segment of length 8.6 Find the length of AC and BC.
Answer:
TS 6th Class Maths Solutions Chapter 13 Practical Geometry Ex 13.3 2

Steps of construction :

  1. Draw a line segment AB = 8.6 cm.
  2. Take A as centre and radius more
    than half of the length AB, draw two arcs above and below the line segment AB. ,
  3. Take B as cfentre and with the same radius, draw two more arcs intersecting the previous- arcs at P and Q.
  4. Join PQ. This line intersects AB at C.
  5. Measure AC and BC. On measuring, it is noticed that AC = BC = 4.3 cm.

TS 6th Class Maths Solutions Chapter 13 Practical Geometry Ex 13.3

Question 3.
Using ruler and compasses, draw AB = 6.4 cm. Find its mid point.
Answer:
We can find the mid point of the line segment AB = 6.4 cm by drawing its perpendicular bisector.
TS 6th Class Maths Solutions Chapter 13 Practical Geometry Ex 13.3 3

Steps of construction:

  1.  Draw a line segment AB = 6.4 cm.
  2. Take A as centre and radius more than half of the length AB draw two arcs above and below the line segment AB.
  3. Take B as centre and with the same radius draw two more arcs intersecting the previous arcs at M and N.
  4. Join MN. This line intersects AB at O. ‘O’ is the mid point of AB.

Leave a Comment