Students can practice Telangana SCERT Class 6 Maths Solutions Chapter 13 Practical Geometry Ex 13.3 to get the best methods of solving problems.
TS 6th Class Maths Solutions Chapter 13 Practical Geometry Exercise 13.3
Question 1.
Draw a line segment PQ = 5.8 cm and construct its perpendicular bisector using ruler and compasses.
Answer:
Steps of construction:
- Draw a line segment \(\overline{\mathrm{PQ}}\) = 5.8 cm.
- Take P as centre and radius more than half of PQ draw two arcs above and below the line segment \(\overline{\mathrm{PQ}}\).
- Take Q as centre and with the same radius, draw two more arcs intersecting the previous arcs at A and B.
- Join A and B. This line intersects PQ at O.
- AB is the required perpendicular bisector of the line PQ.
Question 2.
Ravi made a line segment of length 8.6 Find the length of AC and BC.
Answer:
Steps of construction :
- Draw a line segment AB = 8.6 cm.
- Take A as centre and radius more
than half of the length AB, draw two arcs above and below the line segment AB. , - Take B as cfentre and with the same radius, draw two more arcs intersecting the previous- arcs at P and Q.
- Join PQ. This line intersects AB at C.
- Measure AC and BC. On measuring, it is noticed that AC = BC = 4.3 cm.
Question 3.
Using ruler and compasses, draw AB = 6.4 cm. Find its mid point.
Answer:
We can find the mid point of the line segment AB = 6.4 cm by drawing its perpendicular bisector.
Steps of construction:
- Draw a line segment AB = 6.4 cm.
- Take A as centre and radius more than half of the length AB draw two arcs above and below the line segment AB.
- Take B as centre and with the same radius draw two more arcs intersecting the previous arcs at M and N.
- Join MN. This line intersects AB at O. ‘O’ is the mid point of AB.