{"id":9278,"date":"2024-02-20T10:32:01","date_gmt":"2024-02-20T05:02:01","guid":{"rendered":"https:\/\/tsboardsolutions.in\/?p=9278"},"modified":"2024-02-21T17:13:56","modified_gmt":"2024-02-21T11:43:56","slug":"ts-6th-class-maths-solutions-chapter-13-ex-13-5","status":"publish","type":"post","link":"https:\/\/tsboardsolutions.in\/ts-6th-class-maths-solutions-chapter-13-ex-13-5\/","title":{"rendered":"TS 6th Class Maths Solutions Chapter 13 Practical Geometry Ex 13.5"},"content":{"rendered":"
Students can practice Telangana SCERT Class 6 Maths Solutions<\/a> Chapter 13 Practical Geometry Ex 13.5 to get the best methods of solving problems.<\/p>\n Question 1. Steps of construction:<\/p>\n <\/p>\n Question 2. Steps of construction:<\/p>\n With Using protractor: Steps of construction :<\/p>\n Question 3. Steps of construction:<\/p>\n <\/p>\n (ii) 15\u00b0 Steps of construction:<\/p>\n (iii) 105\u00b0 Steps of construction:<\/p>\n <\/p>\n Question 4. (i) 75\u00b0 Steps of construction:<\/p>\n (ii) 105\u00b0 Steps of construction:<\/p>\n (iii) 15\u00b0 Steps of construction:<\/p>\n Question 5. Steps of construction:<\/p>\n <\/p>\n Question 6. Steps of construction :<\/p>\n Students can practice Telangana SCERT Class 6 Maths Solutions Chapter 13 Practical Geometry Ex 13.5 to get the best methods of solving problems. TS 6th Class Maths Solutions Chapter 13 Practical Geometry Exercise 13.5 Question 1. Construct \u2220ABC = 60\u00b0 without using protractor. Answer: Steps of construction: Draw a line l and choose a point … Read more<\/a><\/p>\n","protected":false},"author":3,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[15],"tags":[],"jetpack_featured_media_url":"","_links":{"self":[{"href":"https:\/\/tsboardsolutions.in\/wp-json\/wp\/v2\/posts\/9278"}],"collection":[{"href":"https:\/\/tsboardsolutions.in\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/tsboardsolutions.in\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/tsboardsolutions.in\/wp-json\/wp\/v2\/users\/3"}],"replies":[{"embeddable":true,"href":"https:\/\/tsboardsolutions.in\/wp-json\/wp\/v2\/comments?post=9278"}],"version-history":[{"count":4,"href":"https:\/\/tsboardsolutions.in\/wp-json\/wp\/v2\/posts\/9278\/revisions"}],"predecessor-version":[{"id":9296,"href":"https:\/\/tsboardsolutions.in\/wp-json\/wp\/v2\/posts\/9278\/revisions\/9296"}],"wp:attachment":[{"href":"https:\/\/tsboardsolutions.in\/wp-json\/wp\/v2\/media?parent=9278"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/tsboardsolutions.in\/wp-json\/wp\/v2\/categories?post=9278"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/tsboardsolutions.in\/wp-json\/wp\/v2\/tags?post=9278"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}TS 6th Class Maths Solutions Chapter 13 Practical Geometry Exercise 13.5<\/h2>\n
\nConstruct \u2220ABC = 60\u00b0 without using protractor.
\nAnswer:
\n<\/p>\n\n
\nConstruct an angle of 120\u00b0 with using protractor and compasses.
\nAnswer:
\nWith using compasses:
\n<\/p>\n\n
\n<\/p>\n\n
\nQ and the line aligned with the \\(\\overline{\\mathrm{QR}}\\).<\/li>\n
\nConstruct the following angles using ruler and compasses. Write the steps of construction in each case.
\n(i) 75\u00b0
\nAnswer:
\n<\/p>\n\n
\n\u2220AOQ = \u2220AOP + \u2220POQ = 60\u00b0 + 60\u00b0 = 120\u00b0<\/li>\n
\nNow \u2220POB = \u2220QOB = 30\u00b0
\n\u2234\u2220AOB = 90\u00b0<\/li>\n
\nNow \u2220POC = \u2220BOC = 15\u00b0<\/li>\n
\n= 60\u00b0 + 15\u00b0
\n= 75\u00b0
\n(or)
\n\u2220AOC = \u2220AOB – \u2220BOC
\n= 90\u00b0 – 15\u00b0
\n= 75\u00b0
\n\u2220AOC is the required angle whose measure is 75\u00b0.<\/li>\n<\/ol>\n
\nAnswer:
\n<\/p>\n\n
\n[\u2220AOC = \u2220BOC = 30\u00b0 ]<\/li>\n
\n[\u2220AOD = \u2220COD = 15\u00b0]<\/li>\n
\nAnswer:
\n<\/p>\n\n
\n\u2234 \u2220BOD = \u2220DOC = \\(\\frac{1}{2}\\) \u2220BOC = \\(\\frac{1}{2}\\) \u00d7 60\u00b0 = 30\u00b0<\/li>\n
\n\u2234 \u2220DOE = \u2220EOC = \\(\\frac{1}{2}\\) \u2220DOC = \\(\\frac{1}{2}\\) \u00d7 30\u00b0 = 15\u00b0<\/li>\n
\nDraw the angles given in Q. 3 using a protractor.
\nAnswer:
\nThe angles given in Q. 3 are 75\u00b0, 105\u00b0 and 15\u00b0.<\/p>\n
\n<\/p>\n\n
\n<\/p>\n\n
\n<\/p>\n\n
\nConstruct \u2220ABC = 50\u00b0 and then draw another angle \u2220XYZ equal to \u2220ABC without using a protactor.
\nAnswer:
\n<\/p>\n\n
\nConstruct \u2220DEF = 60\u00b0. Bisect it, measure each half by using a protractor.
\nAnswer:
\n<\/p>\n\n