{"id":9222,"date":"2024-02-19T02:55:54","date_gmt":"2024-02-18T21:25:54","guid":{"rendered":"https:\/\/tsboardsolutions.in\/?p=9222"},"modified":"2024-02-21T17:11:33","modified_gmt":"2024-02-21T11:41:33","slug":"ts-6th-class-maths-solutions-chapter-13-ex-13-1","status":"publish","type":"post","link":"https:\/\/tsboardsolutions.in\/ts-6th-class-maths-solutions-chapter-13-ex-13-1\/","title":{"rendered":"TS 6th Class Maths Solutions Chapter 13 Practical Geometry Ex 13.1"},"content":{"rendered":"
Students can practice Telangana SCERT Class 6 Maths Solutions<\/a>\u00a0Chapter 13 Practical Geometry Ex 13.1 to get the best methods of solving problems.<\/p>\n Question 1. Steps of construction:<\/p>\n <\/p>\n Question 2. Steps of construction:<\/p>\n Question 3. Steps of construction :<\/p>\n Question 4. Steps of construction:<\/p>\n <\/p>\n Question 5. (ii) Verify \\(\\overline{\\mathbf{A E}}-\\overline{\\mathbf{C E}}\\) = \\(\\overline{\\mathbf{A C}}\\) Question 6. Steps of construction:<\/p>\n Students can practice Telangana SCERT Class 6 Maths Solutions\u00a0Chapter 13 Practical Geometry Ex 13.1 to get the best methods of solving problems. TS 6th Class Maths Solutions Chapter 13 Practical Geometry Exercise 13.1 Question 1. Construct a line segment of length 6.9 cm using a ruler and compasses. Answer: Steps of construction: Draw a line … Read more<\/a><\/p>\n","protected":false},"author":3,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[15],"tags":[],"jetpack_featured_media_url":"","_links":{"self":[{"href":"https:\/\/tsboardsolutions.in\/wp-json\/wp\/v2\/posts\/9222"}],"collection":[{"href":"https:\/\/tsboardsolutions.in\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/tsboardsolutions.in\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/tsboardsolutions.in\/wp-json\/wp\/v2\/users\/3"}],"replies":[{"embeddable":true,"href":"https:\/\/tsboardsolutions.in\/wp-json\/wp\/v2\/comments?post=9222"}],"version-history":[{"count":3,"href":"https:\/\/tsboardsolutions.in\/wp-json\/wp\/v2\/posts\/9222\/revisions"}],"predecessor-version":[{"id":9253,"href":"https:\/\/tsboardsolutions.in\/wp-json\/wp\/v2\/posts\/9222\/revisions\/9253"}],"wp:attachment":[{"href":"https:\/\/tsboardsolutions.in\/wp-json\/wp\/v2\/media?parent=9222"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/tsboardsolutions.in\/wp-json\/wp\/v2\/categories?post=9222"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/tsboardsolutions.in\/wp-json\/wp\/v2\/tags?post=9222"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}TS 6th Class Maths Solutions Chapter 13 Practical Geometry Exercise 13.1<\/h2>\n
\nConstruct a line segment of length 6.9 cm using a ruler and compasses.
\nAnswer:
\n<\/p>\n\n
\nConstruct a line segment of length 4.3 cm using the ruler.
\nAnswer:
\n<\/p>\n\n
\nConstruct a line segment MN of length 6 cm. Mark any point O on it. Measure MO, ON and MN. What do you observe ?
\nAnswer:
\n<\/p>\n\n
\nplace the pencil point upto the 6 cm mark.<\/li>\n
\nIt is noticed that \\(\\overline{\\mathrm{MO}}+\\overline{\\mathrm{ON}}\\) = \\(\\overline{\\mathrm{MN}}\\)<\/li>\n<\/ol>\n
\nDraw a line segment \\(\\overline{\\mathbf{A B}}\\) of length 12 cm. Mark a point C on the line segment \\(\\overline{\\mathbf{A B}}\\), such that \\(\\overline{\\mathbf{A C}}\\) = 5.6 cm. What should be the length of \\(\\overline{\\mathbf{C B}}\\)? Measure the length of \\(\\overline{\\mathbf{C B}}\\).
\nAnswer:
\n<\/p>\n\n
\nGiven that AB = 12 cm
\n
\n(i) From the figure measure the lengths of the following line segments.
\n(a) \\(\\overline{\\mathrm{CD}}\\)
\n(b) \\(\\overline{\\mathrm{DB}}\\)
\n(c) \\(\\overline{\\mathrm{EA}}\\)
\n(d) \\(\\overline{\\mathrm{AD}}\\)
\nAnswer:
\n(a) \\(\\overline{\\mathrm{CD}}\\) = 2.8 cm
\n(b) \\(\\overline{\\mathrm{DB}}\\) = 4.3 cm
\n(c) \\(\\overline{\\mathrm{EA}}\\) = 17.3 cm
\n(d) \\(\\overline{\\mathrm{AD}}\\) = 16.3 cm<\/p>\n
\nAnswer:
\n\\(\\overline{\\mathbf{A E}}-\\overline{\\mathbf{C E}}\\) = 17.3 cm – 3.8 cm = 13.5 cm
\n\\(\\overline{\\mathrm{BC}}\\) = 1.5 cm
\n\\(\\overline{\\mathrm{AC}}\\) = \\(\\overline{\\mathbf{A B}}+\\overline{\\mathbf{B C}}\\)
\n= 12 cm + 1.5 cm
\n= 13.5 cm
\n\u2234 \\(\\overline{\\mathrm{AE}}-\\overline{\\mathrm{CE}}\\) = \\(\\overline{\\mathrm{AC}}\\)<\/p>\n
\n\\(\\overline{\\mathrm{AB}}\\) = 3.8 cm. Construct \\(\\overline{\\mathrm{MN}}\\) by compasses such that the length of \\(\\overline{\\mathrm{MN}}\\) = 3AB’is thrice that of \\(\\overline{\\mathrm{AB}}\\). Verify this with the help of a ruler.
\nAnswer:
\n<\/p>\n\n