{"id":12612,"date":"2024-03-04T10:13:00","date_gmt":"2024-03-04T04:43:00","guid":{"rendered":"https:\/\/tsboardsolutions.in\/?p=12612"},"modified":"2024-03-05T14:19:45","modified_gmt":"2024-03-05T08:49:45","slug":"ts-10th-class-maths-notes-chapter-4","status":"publish","type":"post","link":"https:\/\/tsboardsolutions.in\/ts-10th-class-maths-notes-chapter-4\/","title":{"rendered":"TS 10th Class Maths Notes Chapter 4 Pair of Linear Equations in Two Variables"},"content":{"rendered":"
We are offering TS 10th Class Maths Notes<\/a> Chapter 4 Pair of Linear Equations in Two Variables to learn maths more effectively.<\/p>\n \u2192 An Equation of the form ax + by + c = 0, where a, b, c e R and a and b are not both zero, is called a linear equation in two variables x and y.<\/p>\n \u2192 A pair of linear equations in two variables x and y can be represented as follows : \u2192 A pair of linear Equations in two variables forms a system of simultaneous linear equations. \u2192 A pair of values of the variables x and y satisfying each one of the equations that are given is called a solution of the system. \u2192 A pair of linear equations in two variables can be solved using<\/p>\n <\/p>\n \u2192 Graphical method: The graph of a pair of linear equations in two variables is represented by two straight lines.<\/p>\n \u2192 The relation that exists between the coefficients and nature of system of equations.<\/p>\n \u2192 If a pair of linear equations is given by a1<\/sub>x + b2<\/sub>y + c2<\/sub> = 0 and a2<\/sub>x + b2<\/sub>y + c2<\/sub> = 0, then<\/p>\n Important Formulas:<\/p>\n <\/p>\n Flow Chat: William George Horner(1786 – 1832):<\/p>\n We are offering TS 10th Class Maths Notes Chapter 4 Pair of Linear Equations in Two Variables to learn maths more effectively. TS 10th Class Maths Notes Chapter 4 Pair of Linear Equations in Two Variables \u2192 An Equation of the form ax + by + c = 0, where a, b, c e R … Read more<\/a><\/p>\n","protected":false},"author":2,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[16],"tags":[],"jetpack_featured_media_url":"","_links":{"self":[{"href":"https:\/\/tsboardsolutions.in\/wp-json\/wp\/v2\/posts\/12612"}],"collection":[{"href":"https:\/\/tsboardsolutions.in\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/tsboardsolutions.in\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/tsboardsolutions.in\/wp-json\/wp\/v2\/users\/2"}],"replies":[{"embeddable":true,"href":"https:\/\/tsboardsolutions.in\/wp-json\/wp\/v2\/comments?post=12612"}],"version-history":[{"count":2,"href":"https:\/\/tsboardsolutions.in\/wp-json\/wp\/v2\/posts\/12612\/revisions"}],"predecessor-version":[{"id":12616,"href":"https:\/\/tsboardsolutions.in\/wp-json\/wp\/v2\/posts\/12612\/revisions\/12616"}],"wp:attachment":[{"href":"https:\/\/tsboardsolutions.in\/wp-json\/wp\/v2\/media?parent=12612"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/tsboardsolutions.in\/wp-json\/wp\/v2\/categories?post=12612"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/tsboardsolutions.in\/wp-json\/wp\/v2\/tags?post=12612"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}TS 10th Class Maths Notes Chapter 4 Pair of Linear Equations in Two Variables<\/h2>\n
\na1<\/sub>x + b1<\/sub>y + C1<\/sub> = 0
\na2<\/sub>x + b2<\/sub>y + c2<\/sub> = 0
\nWhere a1<\/sub>, a2<\/sub>, b1<\/sub>, b2<\/sub>, c1<\/sub>, c2<\/sub> are real numbers such that a1<\/sub>2<\/sup> + b1<\/sub>2<\/sup> \u2260 0; a2<\/sub>2<\/sup> + b2<\/sub>2<\/sup> \u2260 0.<\/p>\n
\nExample : 3x – 4y = 2
\n2x + 5y = 9<\/p>\n
\nx = 2, y = 1 is a solution of the system of simultaneous linear equations.
\n3x-4y = 2 …………… (1)
\n2x + 5y = 9 …………… (2)
\nPutting x = 2 and y = 1 in equation (1), we get
\nL.H.S. = 3 \u00d7 2 – 4 \u00d7 1 = 6 – 4 = 2
\nR.H.S = 2
\nL.H.S = R.H.S
\nSimilarly, put x = 2 and y = 1 in equation (2), we get
\nL.H.S = 2 \u00d7 2 + 5 \u00d7 1 = 4 + 5 = 9
\nR.H.S = 9
\n\u2234 L.H.S = R.H.S<\/p>\n\n
\n(a) Substitution method
\n(b) Elimination method
\n(c) Cross-Multiplication method<\/li>\n<\/ul>\n\n
\nIn this case, the pair of equations is inconsistent.<\/li>\n<\/ul>\n\n
\n
\n<\/p>\n\n